Vishal Mehta
Last Activity: 8 Years ago
The no. of vowels in the word are 2. They can be arranged in 2! ways. They can again be arranged in two ways in the beginning and one in the end. So we are left with 5 places which can be taken by any of the nonvowel in 5 ways. Therefore requit no. of ways = 2! × 5!. Number of given letters = 7Total no. of words can be formed = 7!So, required probability= 2!×5!/7!